Find out electric field intensity due to uniformly charged solid non-conducting sphere of volume charge density ρ and radius R at following points:
(i) At a distance r from surface of sphere (inside)
(ii) At a distance r from the surface of sphere (outside)
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(i) 
(ii) 
Sol. (i)

Let us construct a Gaussian surface at distance r from surface of sphere inside it (as shown dotted in figure)
∴ r = R – x or x = R – r
Using Gauss law
;
∴ E. 4π x 2 = 
∴ E =
or E = 
(ii)

Using Gauss law,

⇒ E.4π (R + r) 2 =
;
∴ 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A charge q is placed at the center of the line joining two equal charges Q. The system of the three…
Inside a hollow charged spherical conductor, the potential
Two small spheres each carrying a charge q are placed r meter apart. If one of the spheres is taken…
The electric charge in uniform motion produces
Two charged spheres of radii 10 cm and 15 cm are connected by a thin wire. No current will flow, if…
The electric field inside a spherical shell of uniform surface charge density is