A total charge of 20µC is divided into two parts and placed at some distance apart. If the charges experience maximum coulombian repulsion, the charges should be:
A
5µC, 15µC
B
10µC, 10µC
C
12µC, 8µC
D
Text Solution
Verified by ExpertsThe correct answer is:
B
Let the two charges are q & (20 – q)µC
F e = 
F e will be max, when 
= 0
or 
= 
(20 – 2q) = 0
q = 10µC.
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