A uniform chain of mass m = 1kg and length λ = 1m hangs on a thread and touches the surface of a table by its lower end. Find the force exerted by the table on the chain when x = 0.5m length of chain has fallen on the table. The fallen part does not form heap.
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Weight of the portion BC of the chain
lying on the table, W = 
(downwards) Using v = 
Thrust force F t = v r 
v r = v
= λ v
F t = λ v 2 (where, 
, is mass per unit length of chain)
v 2 = 
= 2gx ∴ F t = 
(2gx) = 2mg 
(downwards)
∴ Net force exerted by the chain on the table is
F = W + F t = 
So, from Newton’s third law the force exerted by the table on the chain will be 
(vertically upwards).
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