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Physics Center of Mass General MCQ (Single Correct)

A man of mass m is at rest on a stationary flat car. The car can move without friction along horizontal rails. The man starts walking with velocity v relative to the car, work done by him m

A
is less than mv 2 if he walks along the rails
B
is equal to mv 2 if he walks normal to the rails
C
can never be less than mv 2
D
is greater than mv 2 if he walks along the rails

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Verified by Experts
The correct answer is:
CHECK THE SOLUTION.

(a, b)

If the man walks along the rails, some velocity say V is imparted to car also. Let M be the mass of car. Then from conservation of linear momentum.

M.V = m(v – V)

∴ V =

∴ work done by man

= m (v – V) 2 + MV 2 = +

= v 2 < mv 2

Hence, option is correct. If the man moves normal to the rails then car will not move. Hence, work done by him in the case will be mv 2 and option is also correct.

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