A bullet of mass m = 1kg strikes a block of mass M =2kg connected to a light spring of stiffness
k =3N/m with a speed V 0 = 3m/s. If the bullet gets embedded in the block then.
Text Solution
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(b, d)
Velocity of the system just after the collision
mv o = (m + M) V ⇒ V = 
Using work energy theorem
Δ K = W AII = W g + W N + W S (Assume friction force is absent) ......(i)
0 – 
(m + M) V 2 = 0 + 0 – 
KX 2 max
= KX 2 max
⇒ X max = 
= 
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