A man of mass 'm' climbs on a rope of length L suspended below a balloon of mass M. The balloon is stationary with respect to ground. If the man begins to climb up the rope at a speed v rel (relative to rope). In what direction and with what speed (relative to ground) will the balloon move?
A
downwards, 
B
upwards, 
C
downwards, 
D
downwards, 
Text Solution
Verified by ExpertsThe correct answer is:
A
we have V m + V b = V rel ⇒ V m = V rel – V b
by conservation of linear momentum
mV m – MV b = 0
So m (V rel – V b ) – MV b = 0
⇒ V b = 
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