A block A of mass m moving with a velocity ' v ' along a frictionless horizontal track and a blocks of mass m/2 moving with 2 v collides with block elastically. Final speed of the block A is :

Text Solution
Verified by ExpertsThe correct answer is:
B
Let the velocities of plank and body of mass 

move with speed v 1 and v 2 after collision as shown.
From conservation of momentum
mv –
2v = mv 1 +
v 2
or 2v 1 + v 2 = 0 ..........
From equation of coefficient of restitution
e = 1 =
⇒ v 2 – v 1 = 3v ..........
Solving 1 and 2 we get
v 1 = v
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