A network of four resistances is connected to 9 V battery, as shown in figure. The magnitude of voltage difference between the points A and B is __________ V
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(3)
The resistance in each branch is 6 
. They are in parallel. So, net resistance is R' = 6/2 = 3 
. The total current flowing through the loop,
Thus, through each branch the current is 1. 5 A.
Hence, the voltage difference across the points is
V A - V B = (4 x 1.5) - (2 x 1.5) = 3 V
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