A block of mass m = 1kg moves on a horizontal circle against the wall of a cylindrical room of radius R = 
m. The floor of the room on which the block moves is smooth but the friction coefficient between the wall and the block is µ= 1. The block is given an initial speed v 0 .
If speed at a instant is v = 2m/s then calculate resultant acceleration of block in m/s 2 at that instant
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(2 m/s 2 )
Sol. 
The normal reaction by wall on the block is N = 
The friction force on the block by the wall is f = µN = 
The tangential acceleration of the block = 
= 
Net acceleration = 
= 
× 
= 2 m/sec 2
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