Two particles A and B move anticlockwise with the same speed v in a circle of radius R and are diametrically opposite to each other. At t = 0, A is imparted a tangential acceleration of constant magnitude a t = 
. If the time in which A collides with B is 
, the angle traced by A during this time is 
, its angular velocity is 
and radial acceleration at the time of collision is 
. Then calculate the value of N 1 + N 2 + N 3 + N 4 .
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(N = 22)
Sol. ω 0( rel) = 0, θ rel = π , α rel = 
θ rel = ω 0( rel) t + 
α rel t 2
π = 0 + 
t 2
t = 
sec. Hence N 1 = 6
Angle traced by A,
θ = 
. 
+ 
. 
= 
+ π = 
π Hence N 2 = 6
angular velocity ω = ω 0 + α t = 
+ 
. 
= 
+ 
= 
Hence N 3 = 5
a c = ω 2 R = 
R = 
Hence N 4 = 5
N 1 + N 2 + N 3 + N 4 = N = 22
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