A uniform metallic chain in a form of circular loop of mass m = 3 kg with a length 
= 1 m rotates at the rate of n = 5 revolutions per second. Find the tension T (in Newton) in the chain.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
T = m λ n 2 = 75 N
Sol. 
dm ω 2 R = 2T sin 
⇒ 
∴ T = 
ω 2 R 2 ....
But ω = 2 π n
λ = 2 π R
∴ T = m λ n 2
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