A particle of mass m is suspended by string of length λ from a fixed rigid support. A sufficient horizontal velocity v 0 = 
is imparted to it suddenly. Calculate the angle (in degree) made by the string with the vertical when the acceleration of the particle is inclined to the string by 45º.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
= 90°
Sol. θ = 
tan 45º = 
⇒ a t = a C
⇒ g sin α = 
...
Using energy conservation
m 3g λ – 
mv 2 = mg λ (1 – cos α )
⇒ mv 2 = 3mg λ – 2mg λ + 2mg λ cos α
mv 2 = mg λ + 2mg λ cos α .............
By eq. and
sin α = 1 + 2 cos α
⇒ α = 90º
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