A track consists of two circular parts ABC and CDE of equal radius 100 m and joined smoothly as shown in fig. Each part subtends a right angle at its center. A cycle weighing 100 kg together with the rider travels at a constant speed of 18 km/h on the track.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
975N, 1025 N, 0,707N, 0,
682N, 732 N, 1.037
Sol- Constant = 18 km/hr = 5m/sec.
m = 100 kg, r = 100 m
at B mg – N B = 
= 
= 25
N B = 975 N Ans.
at D ij N D – mg = 
⇒ N D = 1025 N Ans.
at B & D friction force act is zero.
at C ⇒ f = mg sin 45 = 100 × 10 
( v = constant)
= 707 N Ans.
for BC part
mg cos 45 – N BC = 
⇒ N BC = 682 N
for CD part
N CD – mg cos 45 = 
⇒ N CD = 732 N
f ≤ μ ⇒ μ ≥ 
position where its maximum and N is minimum which is in part BC at C position.
μ ≥ 
⇒ μ ≥ 
= 1.037 Ans
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