Consider a potentiometer circuit, Primary cell is ideal. The length of potentiometer wire is 1m and the resistance per unit length of potentiometer wire varies with length as λ = 2x Ω Ω /m. Where x is distance from end A. Resistance of Rheostat varies with time as R = t 2 Ω Ω . Null deflection point for secondary cell is obtained at x = 
m and at t =1 sec. If emf of secondary cell is 
times of emf of primary cell, find γ.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(8)
Sol λ = 2x
R AB = 
R AB = 1 Ω Ω
R AP = x 2
I = 
= 
Now, V AP = IR AP = E S
⇒ E S = 
⇒ at t = 1sec, x = 
E S = 
= 
⇒ γ = 8
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