A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 s, what is the magnitude and direction of acceleration of the stone ?
A
ms –2 and direction along the radius towards the center
B
π 2 ms –2 and direction along the radius away from center
C
π 2 ms –2 and direction along the radius towards the center
D
π 2 ms –2 and direction along the tangent to the circle
Text Solution
Verified by ExpertsThe correct answer is:
C
Since, speed is constant throughout the motion, so it is a uniform circular motion.
Therefore, its radial acceleration
a = rω 2 = r 
= r × 
= 
= π
2 m/s 2 This acceleration is directed along radius of circle.
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