A particle is projected horizontally from the top of a tower with a velocity v 0 . If v be its velocity at any instant, then the radius of curvature of the path of the particle at that instant is directly proportional to:
Text Solution
Verified by ExpertsThe correct answer is:
A
As we know:
A c = 
(centripetal acceleration)
From figure ; g sin θ = 
⇒ g . 
= 
(Since ; sin θ 1 = 
) ⇒ R α v 3
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