A small block slides with velocity 0.5 
on the horizontal frictionless surface as shown in the Figure. The block leaves the surface at point C. The angle θ in the Figure is :
Text Solution
Verified by ExpertsThe correct answer is:
B
Given v B = 0.5 
Assume block leave the contact at C, N = 0
= mg cos θ .... (i)
from energy conservation 
mv B 2 + mgr (1 – cos θ) = 
mv c 2 ........... (ii)
from equation and .
m 
+ mg r (1 – cos θ) = 
mg r cos θ
⇒ cos θ = 
⇒ θ = 
cos –1
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