A particle moves along a circle of radius 
m with constant tangential acceleration. If the speed of the particle is 80 m/s at the end of the second revolution after motion has begun, the tangential acceleration is:
Text Solution
Verified by ExpertsThe correct answer is:
C
r = 
m, a t = constant
n = 2 nd revolution
v = 80 m/s
ω 0 = 0, ω f = 
= 
= 4πrad/sec
θ = 2π × 2 = 4π
from 3 rd equation
ω 2 = ω 0 2 + 2αθ
(4π) 2 = 0 2 + 2 × α × (4π)
α = 2πrad/s 2
a t = αr = 2π × 
= 40 m/s 2
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