and (1): The curve appears to be horizontal, and v y = 0. As the wave moves, the point will begin to move downward, and a y < 0. (2): As the wave moves in the +x-direction, the particle will move upward so v y >0. The portion of the curve to the left of the point is steeper, so a y > 0. (3): The point is moving down, and will increase its speed as the wave moves; v y < 0, a y < 0. (4): The curve appears to be horizontal, and v y = 0. As the wave moves, the point will move away from the x-axis, and a y > 0. (5): The point is moving downward, and will increase its speed as the wave moves; v y < 0, a y < 0. (6): The particle is moving upward, but the curve that represents the wave appears to have no curvature, so v y > 0 and a y = 0.

The accelerations, which are related to the curvatures, will not change. The transverse velocities will all change sign.