Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. Speaker B is 12.0 m to the right of speaker A. The frequency of the waves emitted by each speaker is 688 Hz. You are standing between the speakers, along the line connecting them and are at a point of constructive interference. How far must you walk toward speaker B to move to a point of destructive interference?
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
λ= v/f = (344 m/s)/(688 Hz) = 0.500 m
To move from constructive interference to destructive interference, the path difference must change by λ /2. If you move a distance x toward speaker B, the distance to B gets shorter by x and the difference to A gets longer by x so the path difference changes by 2x.
2x = λ/2 and x = λ/4 = 0.125 m.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems