A car accelerates from rest at a constant rate of 2 ms –2 for some time. Then it retards (speed decrease) at a constant rate of 4 ms –2 and comes to rest. It remains in motion of 6 s.
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(a, c)
Car goes from A to B under acceleration 2m/s 2 and from B to C under retardation.
V B = V A + a 1 t AB
V B = 0 + (2m/s 2 ) t AB …(i)
AB = 
× (2m/s 2 ) 
= (1m/s 2 ) 
…(ii)
V C = V B + a 2 t BC
0 = 2(m/s 2 )t AB + (– 4m/s 2 ) t BC
0 ⇒ t AB = 2 t BC …(iii)
Given t AB + 2 t BC = 6s …..(iv)
from (iii) and (iv)
t AB = 4s ; t BC = 2s
from (i)
V B = 8m/s ; AC = 24m`
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