A railway compartment is 16 m long, 2.4 in wide and 3.2 m high. It is moving with a velocity v. A particle moving horizontally with a speed u, perpendicular to the direction of v, enters through a hole at an upper corner A and strikes the diagonally opposite corner B. Assume g= 10 m/s 2 .

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Consider the vertical motion of the particle after entering compartment. Let it reach the floor in time t.
3.2 =
(10)t 2 or t = 0.8 s
Due to the velocity component u, which remains constant, it covers a distance of 2.4 m is 0.8 s.
∴ ∴ u = 2.4 m/0.8 s = 3 m/s
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