Path of a particle moving in x-y plane is y = 3x + 4. At some instant suppose x-component of velocity is 1m/s and it is increasing at a rate of 1 m/s 2 . Then at this instant -
A
speed of particle is 
m/s
m/s
B
acceleration of particle is 
m/s 2
m/s 2
C
velocity-time graph is a straight line
D
acceleration-time graph is a straight line
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION
(a, b) y = 3x + 4
= 
v y = 3v x = 3 (As v 2 = 1 m/s)
= 
a y = 3a x = 3 (as a x = 1m/s)
nothing can be said about velocity & acceleration as the given values are at particular instant.
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