A boy standing on a long railroad car throws a ball straight upwards. The car is moving on the horizontal road with an acceleration of 1m/s 2 and projection velocity in the vertical direction is 9.8m/s. How far behind the boy will the ball fall on the car ? (in m)
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Ans. 2
Sol. Time when velocity of ball is zero
0 = 9.8 × gt ⇒ t = 
= 1s.
∴ total time when it comes back = 2s
distance travelled by trolley in 2s
s = 
at 2 = 
× 1 × 2 2 = 2m.
ball will fall 2m behind the boy.
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