A boy is throwing balls into the air, throwing one whenever the previous one is at its highest point. How high do the balls rise if he throws twice a second ?
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Sol. Suppose that the boy throws n time a second. Then the time of flight of each ball upwards t = 1/nsec. The time of rise equals the time of fall. But the distance and time of fall are connected by the formula
s = 
= 
Therefore the height equals
s = 
≈ 
≈ 1.23 m.
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