A body hanging from a spring stretches it by 1 cm at the earth’s surface. How much will the same body stretch the spring at a place 16400 km above the earth’s surface? (Radius of the earth = 6400 km)
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B
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Text Solution
Verified by ExpertsThe correct answer is:
B
In equilibrium, weight of the suspended body = stretching force.
At the earth’s surface, mg = k × x
At a height h, mg` = k × x`
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