An ideal gas heat engine operates in Cannot cycle between 227ºC and 127ºC. It absorbs 6 × 10 4 cal of heat at higher temperature. Amount of heat converted to work is:
Text Solution
Verified by ExpertsThe correct answer is:
C
The heat converted to work is the amount of heat that remains after going through sink.
From the relation

Given Q 1 = 6 × 10 4 cal,
T 1 = 227 + 273 = 500K
T 2 = 127 + 273 = 400 K
∴
⇒ Q 2 =
= 4.8 × 10 4 cal
Now, heat converted to work = Q 1 – Q 2
= 6.0 × 10 4 – 4.8 × 10 4
= 1.2 × 10 4 cal
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