An equilateral triangle ABC is cut from a thin solid sheet of wood. (See figure) D, E and F are the mid- points of its sides as shown and G is the centre of the triangle. The moment of inertia of the triangle about an axis passing through G and perpendicular to the plane of the triangle is I 0 . If the smaller triangle DEF is removed from ABC, the moment of inertia of the remaining figure about the same axis is I. Then :
Text Solution
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From Dimension analysis I 0 = kMa 2
Now for small lamina
I ' = k 
I ' = 
So moment of inertia of remaining part I – I ' = 
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