A string is wound around a hollow cylinder of mass 5 kg and radius 0.5 m. If the string is now pulled with a horizontal force of 40 N, and the cylinder is rolling without slipping on a horizontal surface (see figure), then the angular acceleration of the cylinder will be (Neglect the mass and thickness of the string):
Text Solution
Verified by ExpertsThe correct answer is:
B
Taking torque about the point of contact
40 × [1] = [mr 2 + mr 2 ] α
40 = 2m × 
α
40 = 2 × 5 × 
α .
∴ α = 16 rad/s 2
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