A particle of mass 20 g is released with an initial velocity 5 m/s along the curve from the point A, as shown in figure. The point A is at height h from point B. The particle sides along the frictionless surface. When the particle reaches point B, its angular momentum about O will be :
Text Solution
Verified by ExpertsThe correct answer is:
B
Applying conservation of energy
mgR = 
V 2 = 
= 
V 2 = 15 m/s
L 0 = mV B r
= 20 × 10 –3 × 20 × 15
L 0 = 6 kgm 2 /s
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