From the given data, the amount of energy required to break the nucleus of aluminium 
is 
Mass of neutron = 1.00866u
Mass of proton = 1.00726u
Mass of Aluminium nucleus =27.18846u
(Assume 1 u corresponds to xJ of energy) (Round off to the nearest integer)
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(27)
= (13 × 1.00726 + 14 × 1.00866) − 27.18846
= 27.21562 − 27.18846
= 0.02716u
E = 27.16x × 10 −3 J
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