Published by:
CGP EDU Academic Team
Published on: September 13, 2026
From the given data, the amount of energy required to break the nucleus of aluminium 
is 
Mass of neutron = 1.00866u
Mass of proton = 1.00726u
Mass of Aluminium nucleus =27.18846u
(Assume 1 u corresponds to xJ of energy) (Round off to the nearest integer)
Text Solution
Verified by ExpertsThe correct answer is:
27
(27)
= (13 × 1.00726 + 14 × 1.00866) − 27.18846
= 27.21562 − 27.18846
= 0.02716u
E = 27.16x × 10 −3 J
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Mass numbers of two nuclei are in the ratio of 4 : 3. Their nuclear densities will be in the ratio …
Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below:
Th…
If the binding energy of ground state electron in a hydrogen atom is 13.6 eV, then, the energy requ…
Nucleus a having Z = 17 and equal number of protons and neutrons has L2 MeV binding energy per nucl…
Energy released when two deuterons fuse to form a helium nucleus is:
(Given: Binding energy per n…
For a nucleus of mass number and radius , the mass density of nucleus can be represented as