A bullet of mass 0.01kg and travelling at a speed of 500 m/s strikes and passes horizontally through a block of mass 2kg which is suspended by a string of length 5m. The centre of gravity of the block is found to raise a vertical distance of 0.1 m. What is the speed of the bullet after it emerges from the block. [ g = 9.8m/s 2 ] (time of passing of bullet is negligible)
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220 m/s
P i = .01 × 500 = 5 kg m/sec
P f = m b V b + m block × V block
V block = 
= 
= 1.4 m/sec
P i = P f = 5 = 0.01 × V b + 2 × 1.4
V b = 
= 220m/sec.
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