A particle of mass m moving with a speed v hits elastically another stationary particle of mass 2m in a fixed smooth horizontal circular tube of radius r. Find the time when the next collision will take place?
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
t = 
Sol. Particle B is a rest
mv + 0 = mv 1 + 2mv 2
∴ v = v 1 + 2v 2 .....(i)
= 1
⇒ v 2 – v 1 = v .....(ii)
Adding (i) + (ii)
3v 2 = 2v
∴ v 2 = 
v v 1 = v 2 – v = 
Now (iii) + (iv)
t = 
= 
t = 
Ans.
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