A nucleus with mass number 242 and binding energy per nucleon as 7.6 MeV breaks into two fragment each with mass number 121. If each fragment nucleus has binding energy per nucleon as 8.1 MeV , the total gain in binding energy is MeV.
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(121)
Binding energy is given by 
where 
is the mass defect.
The energy per nucleon of the nucleus having mass number 242 is 7.6 MeV .
The initial binding energy is,
The energy per nucleon of the nucleus with mass number 121 is 8.1 MeV .
Therefore, binding energy is
The gain in the binding energy is
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