The box of a pin hole camera, of length L, has hole of radius a. it is assumed that when the hole is illuminated by a parallel beam of light of wavelength λ the spread of the spot (obtained on the opposite wall of the camera) is the sum of its geometrical spread and the spread due to diffraction. The spot would then have its minimum size (say b min ) when :
A
and 
B
and 
C
and 
D
and 
Text Solution
Verified by ExpertsThe correct answer is:
B
Sol. b → radius of spot.
b = a + 
geometrical spread + spread due to diffraction
= 0
⇒ 1 – 
= 0 ⇒ a 2 = L λ ⇒ a = 
b min. = 
b min. = 
b min. = 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A slit of width ‘a’ is illuminated by light of wavelength 6000 A 0 For What value of ‘a will the :-…
Two coherent sources produce waves of different intensities which interfere. After interference, th…
<p>In Young's double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength λ = …
In a double-slit experiment, green light (5303Å) falls on a double slit having a separation of 19.4…
Consider a tank made of glass (refractive index 1.5) with a thick bottom. It is filled with a liqui…
Visible light of wavelength falls normally on single slit and produces a diffraction pattern. It i…