Home Physics Wave Optics JEE (Main) / AIEEE Problems ( Previous Years ) The angular width of the central maximum in …
Physics Wave Optics JEE (Main) / AIEEE Problems ( Previous Years ) MCQ (Single Correct)

The angular width of the central maximum in a single slit diffraction pattern is 60°. The width of the slit is 1 μ m. The slit is illuminated by monochromatic plane waves. If another slit of same width is made near it, Young's fringes can be observed on a screen placed at a distance 50 cm from the slits. If the observed fringe width is 1 cm, what is slit separation distance?

(i.e. distance between the centres of each slit.)

A
75 μ m
B
100 μ m
C
25 μ m
D
50 μ m

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
C

Sol.

Semi-angular width = 30°

asin θ = λ

asin30° = λ

Fringe width =

⇒ d = = 25 μ m

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.