Physics Simple Harmonic Motion (Oscillations) JEE Main / Advanced Problems ( Previous Years) MCQ (Single Correct)

In the column-I, a system is described in each option and corresponding time period is given in the column-II. Suitably match them.

Column-I

Column-II

(a)

A simple pendulum of length 'λ' oscillating with small amplitude in a lift moving down

with retardation g/2.

(p)

T = 2π

(b)

A block attached to an

end of a vertical spring,

whose other end is

fixed to the ceiling of a

stationary lift, stretches

the spring by length 'λ'

in equilibrium. It's time

period when lift moves

up with an acceleration

g/2 is

(q)

T = 2π

(c)

The time period of small oscillation of a uniform rod of length 'λ' smoothly hinged at one end. The rod oscillates in vertical plane.

(r)

T = 2π

(d)

A cubical block of edge

'λ' and specific gravity

1/2 is in equilibrium

with some volume

inside water filled in a

large fixed container.

Neglect viscous forces

and surface tension.

The time period of

small oscillations of the

block in vertical

direction is

(s)

T = 2π

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Text Solution

Verified by Experts
The correct answer is:
CHECK THE SOLUTION.

p, q, p, s

Sol. In frame of lift effective acceleration due to gravity is downwards

∴ T = 2 π

K λ = mg

constant acceleration of lift has no effect in time period of oscillation.

∴ T = 2 π = 2 π

T = 2 π = 2 π

T = 2 π = 2 π = 2 π

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