Assuming that about 20 MeV of energy is released per fusion reaction, 1 H 2 + 1 H 3 → 0 n 1 + 2 He 4 , the mass of 1 H 2 consumed per day in a future fusion reactor of power 1 MW would be approximately
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Verified by ExpertsThe correct answer is:
A
no of moles of 1 H 2 consumed
= 
= 0.05
m = 0.1 g
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