Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Two blocks of masses m and M are moving with speeds v 1 and v 2 (v 1 > v 2 ) in the same direction on the frictionless surface respectively, M being ahead of m. An ideal spring of force constant k is attached to the backside of M (as shown). The maximum compression of the spring when the block collides is :
A
v 1 
B
v 2 
C
(v 1 – v 2 ) 
D
None of above is correct
Text Solution
Verified by ExpertsThe correct answer is:
C
P i = mv 1 + mv 2
P f = (m + M) v
P i = P f ⇒ v = 
By energy consarvation
mv 1 2 + 
Mv 2 2 = 
(M + m) v 2 + 
kx 2
⇒ mv 1 2 + Mv 2 2 = (M + m) 
Solving x = (v 1 –v 2 ) 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Two masses are connected by a spring as shown in the figure. One of the masses was given velocity v…
Mass A hits B inelastically (e = 0) while moving horizontally with some velocity along the common l…
In the figure shown the change in magnitude of momentum of the block when it comes to its initial p…
Two masses m 1 and m 2 are connected by a spring of spring constant k and are placed on a smooth ho…
Two block of masses m 1 and m 2 are connected with the help of a spring of spring constant k initia…
Two blocks A and B of mass m A and m B are connected together by means of a spring and are resting …