Two block of masses m 1 and m 2 are connected with the help of a spring of spring constant k initially the spring in its natural length as shown. A sharp impulse is given to mass m 2 so that it acquires a velocity v 0 towards right. If the system is kept on smooth floor then find
A
the velocity of the centre of mass,
B
the maximum elongation that the spring will suffer ? 
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Sol.
x cm = 
= V cm = 
V cm = 
Ans.
F = 0 ; p = constant
m 2 v 0 = (m 1 +m 2 )v
& 
m 2 
= 
m 1 v 2 + 
m 2 v 2 + 
k 
V cm → remain unchanged
∴ 
m 2 
= 
(m 1 + m 2 ) 
+ 
k 
m 2 
= k 
∴ m 2 
= k 
= 
⇒ x 0 = v 0 
Ans
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