Two blocks of masses m and M are moving with speeds v 1 and v 2 (v 1 > v 2 ) in the same direction on the frictionless surface respectively, M being ahead of m. An ideal spring of force constant k is attached to the backside of M (as shown). The maximum compression of the spring when the block collides is :
A
v 1 
B
v 2 
C
(v 1 – v 2 ) 
D
None of above is correct
Text Solution
Verified by ExpertsThe correct answer is:
C
P i = mv 1 + mv 2
P f = (m + M) v
P i = P f ⇒ v = 
By energy consarvation
mv 1 2 + 
Mv 2 2 = 
(M + m) v 2 + 
kx 2
⇒ mv 1 2 + Mv 2 2 = (M + m) 
Solving x = (v 1 –v 2 ) 
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