A projectile is fired vertically upwards with an initial velocity u . After an interval of T seconds a second projectile is fired vertically upwards, also with initial velocity u .
Text Solution
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For first projectile, \(\hbar - \hbar^* - \frac{1}{2} g^{*}\)
For second projectile, \(h_2 = u(t - T) - \frac{1}{2} g (t - T)^2\)
When both meet i.e. \(h \quad h_2\)
\(\alpha - \frac{1}{2} g t^{2} - u (t - T) - \frac{1}{2} g (t - T)^{2}\)
⇒ ⇒ \(\upsilon T + \frac{1}{2} g T^{i} - g T\)
⇒ ⇒ \(\ell = \frac{v}{g} + \frac{T}{2}\)
and \(h_1 = u \left| \frac{u}{g} + \frac{T}{2} \right| \cdot \frac{1}{2} g \left| \frac{u}{2} + \frac{T}{2} \right|^2\)
\(-\frac{U^{c}}{2g} - \frac{gT^{c}}{8}\) .
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