A ball is dropped vertically from a height \dot{d} above the ground. It hits the ground and bounces up vertically to a height \(\delta/2\) . Neglecting subsequent motion and air resistance, its velocity \vec{v} varies with the height h above the ground is
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For the given condition initial height \hbar = d and velocity of the ball is zero. When the ball moves downward its velocity increases and it will be maximum when the ball hits the ground & just after the collision it becomes half and in opposite direction. As the ball moves upward its velocity again decreases and becomes zero at height d/2 . This explanation match with graph ( A ).
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