Steam is passed into 22 gm of water at 20°C. The mass of water that will be present when the water acquires a temperature of 90°C (Latent heat of steam is 540 cal/gm) is
Text Solution
Verified by ExpertsThe correct answer is:
A
Let m gm of steam get condensed into water (By heat loss). This happens in following two
steps.
Heat gained by water (20°C) to raise it’s temperature upto 90° 
Hence, in equilibrium heat lost = Heat gain
⇒ ⇒ 
⇒ ⇒ 
gm
The net mass of the water present in the mixture 
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