In the figure, $s_{1}$ and $S_2$ are identical springs. The…

Physics Simple Harmonic Motion (Oscillations) Spring Pendulum Single Correct MCQ

Published on: September 12, 2026

In the figure, $s_{1}$ and $S_2$ are identical springs. The oscillation frequency of the mass m is f . If one spring is removed, the frequency will become

$f \times 2$

$f \times \sqrt{2}$

$f/\sqrt{2}$

Text Solution

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The correct answer is:

For the given figure $f = \frac{1}{2 \pi} \sqrt{\frac{k_{eq}}{m}} = \frac{1}{2 \pi} \sqrt{\frac{2k}{m}}$ …...(i)

If one spring is removed, then k eq = k and

$f' = \frac{1}{2 \pi} \sqrt{\frac{k}{m}}$ …. (ii)

From equation (i) and (ii),

$\frac{f}{f'} = \sqrt{2}$ ⇒ ⇒ $f' = \frac{f}{\sqrt{2}}$

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