A mass m =100 gms is attached at the end of a light spring …

Physics Simple Harmonic Motion (Oscillations) Spring Pendulum Single Correct MCQ

Published on: September 12, 2026

A mass m =100 gms is attached at the end of a light spring which oscillates on a frictionless horizontal table with an amplitude equal to 0.16 meter and time period equal to 2 sec. Initially the mass is released from rest at t = 0 and displacement $x = -0.16$ meter. The expression for the displacement of the mass at any time t is

$x = 0.16 \cos(\pi t)$

$x = -0.16 \cos(\pi t)$

$x = 0.16 \sin(\pi t + \pi)$

$x = -0.16 \sin(\pi t + \pi)$

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The correct answer is:

Standard equation for given condition

$x = a \cos \frac{2 \pi}{T} t$ ⇒ ⇒ $x = -0.16 \cos(\pi t)$

[As a = – 0.16 meter, T = 2 sec]

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