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CGP EDU Academic Team
Published on: September 12, 2026
A mass m attached to a spring oscillates every 2 sec. If the mass is increased by 2 kg, then time-period increases by 1 sec. The initial mass is
Text Solution
Verified by ExpertsThe correct answer is:
A
$T = 2 \pi \sqrt{\frac{m}{k}} \Rightarrow \frac{T_2}{T_1} = \sqrt{\frac{m_2}{m_1}}$ ⇒ ⇒ $\frac{3}{2} = \sqrt{\frac{m+2}{m}}$ 
$\frac{9}{4} = \frac{m+2}{m}$
$\Rightarrow m = \frac{8}{5} \mathrm{kg} = 1.6 \mathrm{kg}$
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