A

Step 1: Identify the given parameters:
Radius of the circle, r = 25 cm = 0.25 m (since 1 cm = 0.01 m)
Revolutions per second, f = 2 rev/s.

Step 2: Calculate the angular velocity, \( \omega \):
Angular velocity is given by the formula: \( \omega = 2\pi f \)
Substituting the values:
\( \omega = 2\pi \times 2 = 4\pi \) radians per second.

Step 3: Calculate the centripetal acceleration, \( a_c \):
The formula for centripetal acceleration is given by: \( a_c = \frac{v^2}{r} \)
To find the linear velocity v, we use the relation: \( v = \omega r \)
Substituting for v:
\( v = (4\pi)(0.25) = \pi \) m/s.
Now, substituting v into the centripetal acceleration formula:
\( a_c = \frac{(\pi)^2}{0.25} = \frac{\pi^2}{0.25} = 4\pi^2 \)

Step 4: Calculate the numerical value of \( 4\pi^2 \):
Using \( \pi \approx 3.14 \):
\( 4\pi^2 \approx 4 \times (3.14)^2 \approx 4 \times 9.86 \approx 39.44 \) m/s².

Final Answer: Therefore, the acceleration of the particle is approximately 39.44 m/s².