Home Physics Work, Energy, Power and Collision JEE Main 2023 A force acts on a particle in the x directi…
Physics Work, Energy, Power and Collision JEE Main 2023 MCQ (Single Correct)

A force acts on a particle in the x direction where F is in Newton and x is in meter. The work done by this force during a displacement from x = 0 to x = 4 m is_____J.

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The correct answer is:
CHECK THE SOLUTION.

(32)

The formula to calculate the work done by a variable force is given by

...

Substitute the values of the known parameters into equation to calculate the required work done.

= [8 + 24] J

=32 J

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