A box having mass 400 kg is to be slowly slide through 10 m on a horizontal straight track having friction coefficient 0.2 with the box.
Text Solution
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7692.31 J, 7690 J
Sol.

mg = N + F sin θ.......(1)
µN = F cos θ .......(2)
µmg = F cos θ + µF sin θ
F =
.......(3)
W F =
=
Ans.
F is min. if D = cos θ + µ sin θ is maximum and its maximum value is 
F min. =
= 
=

µ = 0.2, mg = 4000 Nt
= 
=
=
= 7692.307 J Ans.
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